Between 6 a. m. and 10 a. m. the temperature rose by 5°F. Between 10 a. m. and 2 p. m. the temperature rose by 6°F. Between 2 p. m. and 6 p. m. the temperature rose by 0°C. Would you be able to tell how much the temperature rose since 6 a. m.? Why or why not?

So the total increase is 15C

Step-by-step explanation:

Yes, we can able to know the temperature difference from 6 AM to 6 PM.

We need to convert all the temperature into one unit.

6 AM - 10 AM ---> 5 F = -15 C

10 AM - 2 PM ---> 6 F = -14.44 C

2 PM - 6 PM ---> 0 C.

So the total increase is 15C

hope this helped :)

6hryt%4578855

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.