Which of the points (s, t) is not one of the vertices of the shaded region of the
set of inequalities shown below?
Ss 12 -0.5t
s 10-t
SS 20-t
S20
t> 0
O A. (16,4)
B. (4,16)
O C. (0,10)
D. (0,20)

C. (0,10)

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

Please have a look at the attached photo.   Because I have answered this question one in Branily

My

Given the 4 inequalities:

Let analyse all 4 possible

Let substitute this point into (1) we have: 10 ≥ 12 -0.5*0 Wrong

We do not choose A

Let substitute this point into (1) we have: 20 ≥ 12 -0.5*0  True

Let substitute this point into (2) we have: 20 ≥ 10 - 0 True

Let substitute this point into (3) we have: 20 ≤ 20 - 0 True

We choose B as the vertex

Let substitute this point into (1) we have: 16 ≥ 12 -0.5*4  True

Let substitute this point into (2) we have: 16 ≥ 10 - 4 True

Let substitute this point into (3) we have: 16 ≤ 20 - 4 True

We choose C as the vertex

Let substitute this point into (1) we have: 4 ≥ 12 -0.5*16 True

Let substitute this point into (2) we have: 4 ≥ 10 - 16 True

Let substitute this point into (3) we have: 4 ≤ 20 - 16 True

We choose B as the vertex

Hence, the point A (0,10)  is not one of the vertices of the shaded region of the  set of inequalities.

the answer to this question is yes

the correct answer is b. negative exponential growth.

step-by-step explanation:

you can tell it's an exponential function because it decreases rapidly then levels out and never touches the x-axis.

it is negative because the y-axis decreases as the x-axis increases.

therefore it is a negative exponential growth graph.

hope i !