The function E(d)=0.25d√ approximates the number of seconds it takes a dropped object to fall d feet on Earth. The function S(d)=0.2⋅E(d) approximates the number of seconds it takes a dropped object to fall d feet on the sun. How long (in seconds) does it take a dropped object to fall 80 feet on the sun? Round your answer to the nearest hundredth.

0.45 second

Step-by-step explanation:

The number of seconds it takes a dropped object to fall d feet on Earth is given as:

E(d)=0.25√d

the number of seconds it takes a dropped object to fall d feet on the sun is given as:

S(d)=0.2⋅E(d)

Therefore

S(d)=0.2 × 0.25√d = 0.05√d

Given that it take a dropped object to fall 80 feet on the sun (i.e d = 80 feet), to calculate the time in seconds we use:

S(d) = 0.05√d

S(d) = 0.05 × √80 = 0.05 × 8.944 ≈ 0.45 s

It takes 0.45 second for a dropped object to fall 80 feet on the sun

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it