A salon and spa chain periodically analyzes its service times to check for variation in service processes. To do this, it uses R-charts. Seven samples, each containing observed service time with three different customers, were collected. The average mean and the average range of the service times are found to be 9.924 and 0.957, respectively. If D 4 for the R-chart is 1.924, the upper control limit (UCLr=D4*Rbar) for the R-chart will be:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²

2

step-by-step explanation:

i dont know

step-by-step explanation:

the reason i dont know is because i have not taken this class and for that reason i haven't learned this stuff

hope i could