Please help!

Curious Carl calculated the density of a cube to be 4.50 g/cm3. What is the density of the cube in g/L?
A) 4.50 g/L
B) 45.0 g/L
C) 4500 g/L
D) 45000 g/L

C) 4500 g/L

Step-by-step explanation:

1 L = 1000 cubic centimetres (cm³)

1 cm³ = L

Density of cube = 4.50 g/cm³

= 4.50 × g/L

= 4.50 × 1000 g/L

= 4500 g/L

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

x + 4/7

step-by-step explanation:

use cymath