An observer (O) is located 500 feet from a school (S). The observer notices a bird (B) flying at a 39° angle of elevation from his line of sight. How high is the bird flying over the school? You must show all work and calculations to receive full credit.

404.9ft

Step-by-step explanation:

The observer O is at a distance of 500ft from a building S.

The observer makes an angle of elevation with a bird B at θ = 39°

The height of the bird from the ground = h

See attached document for better illustration.

Using SOHCAHTOA,

Tanθ = opposite/ adjacent

θ = 39°

Adjacent = 500

Opposite = h

Tan39 = h / 500

h = 500 × tan39

h = 500 × 0.8098

h = 404.9ft the height of the bird from the ground is 404.9ft or the bird is flying at 404.9ft high over the school

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10