What is the solution to the system of equations below?
y = -3/4x + 3 and y = –12

1. (20, -12)
2. (12, -12)
3. (-6,-12)
4. (-12,12)

(20, -12)

Step-by-step explanation:

it is (20, -12)

-(3/4)x+3=-12

x=20

-3/4(20)+3=-12

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~