To approach the runway, a pilot of a small plane must begin a 5 degree descent starting from a height of 1407 feet above the ground. To the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this approach?

  3.0 miles

Step-by-step explanation:

The tangent of the angle relates the opposite side (altitude) to the adjacent side (distance to runway):

  tan(5°) = (altitude)/(distance to runway)

Then we have ...

  distance to runway = (1407 ft)/(tan 5°) ≈ 16,082 ft

In miles, that is ...

  distance to runway = (16082 ft)/(5280 ft/mi) = 3.0458 mi

The pilot is 3.0 miles from the runway at the start of his approach.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

the ratio of grapes to blueberries she should use is 12: 3

step-by-step explanation:

if mandie is making 15 cups of fruit salad, the ratio of grapes to blueberries she should use is 12: 3.