The dot plot shows how many attempts it took for each student to complete a puzzle:

Dot plot titled Puzzle Attempts and labeled Number of Attempts shows number line from 1 to 10. There are no dots over 1 and 10, 1 dot over 2 and 9, 2 dots over 3 and 8, 3 dots over 4 and 7, 5 dots over 5 and 6.

Is the median or the mean a better measure of center for these data and why?

Mean, because the data are skewed and there are outliers
Mean, because the data are symmetric and there are no outliers
Median, because the data are skewed and there are outliers
Median, because the data are symmetric and there are no outliers

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

step-by-step explanation:

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.