Rearrange w=3(2a+b)-4 to make a the subject

w = 3(2a + b) - 4

First, add 4 to both sides:

w (+4) = 3(2a + b) - 4 (+4)

w + 4 = 3(2a + b)

Next, divide 3 from both sides:

(w + 4)/3 = (3(2a + b))/3

(w + 4)/3 = 2a + b

Next, subtract b from both sides:

((w + 4)/3) - b = 2a + b (-b)

(w + 4)/3 - b = 2a

Finally, divide 2 from both sides:

((w + 4)/3 - b)/2 = (2a)/2

a = (((w + 4)/3) - b)/2

a = (((w + 4)/3) - b)/2 is your answer.

~

=a

Step-by-step explanation:

w=3(2a+b)-4 ---> add 4 to both sides

w+4=3(2a+b) --> distribute the 3

w+4= 6a+3b--> subtract 3b from both sides

w+4-3b=6a ---> to isolate the a divide both sides by 6

= a ---> I hope this was what you were looking for

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

what "following statement"?

step-by-step explanation: