Please help me and then solve for angle 2 please I really need help

Angle 1 is 45

Angle 2 is 90

Step-by-step explanation:

ABCD is a square, so by definition, all of its angles equal 90:

∠ABC = ∠BCD = ∠CDA = ∠DAB = 90

We also see that AC and BD are diagonals of the square, and by definition, these diagonals bisect those angles. In other words, these diagonals cut those angles in half.

∠DAB = ∠DAE + ∠BAE

That means ∠DAE = ∠BAE = 90/2 = 45 degrees, which also means angle 1 is 45 degrees.

Also by definition, when the diagonals intersect, they form a right angle. In other words, angle 2 will be 90 degrees.

Thus, the answer is angle 1 is 45 and angle 2 is 90.

1: 45°

2: 90°

Step-by-step explanation:

Diagonals of a square are Perpendicular bisectors of each other, hence AEB is an isosceles right angle triangle

Angle at E = 90

Angle at A = (180-90)/2 = 45

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17