A standard deck of 525252 cards contains 444 suits: hearts, clubs, diamonds, and spades. Each suit consists of cards numbered 222 through 101010, a jack, a queen, a king, and an ace. Anthony decides to pick one card at random from a standard deck of 525252 cards. Let AAA be the event that he chooses an ace and HHH be the event that he chooses a heart. What is P(A\text{ or }H)P(A or H)P, left parenthesis, A, start text, space, o, r, space, end text, H, right parenthesis, the probability that the card Anthony chooses is either an ace or a heart?

The question is not properly written

Correct Question

A standard deck of 52 cards contains 4 suits: hearts, clubs, diamonds, and spades. Each suit consists of cards numbered 2 through 10, a jack, a queen, a king, and an ace.

Anthony decides to pick one card at random from a standard deck of 52 cards. Let A be the events that he chooses an ace and H be the event that he chooses a heart.

What is P ( A or H), the probability that the card Anthony chooses is either an ace or a heart?

2/13

Step-by-step explanation:

From the question, we have in total, 52 cards.

Step 1

We find the probability that Anthony chooses an Ace.

Number of ace cards in each of four suits namely spades, hearts, diamonds and clubs = 1

Therefore, total number of ace cards out of 52 cards = 4

P(A) = 4/52

Step 2

We find the probability that Anthony chooses an Ace.

Probability that Anthony chooses an heart P(H) = 4/52

Step 3

The probability that the card Anthony chooses is either an ace or a heart

P ( A or H) = P(A) + P(H)

= 4/52 + 4/52

= 8/ 52 = 2 /13

is this part of a question or something

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3