Find two numbers whose square increased by 15 equals 8 times the number.

5 and 3

So we let the number take the letter b, anc the expression of the question is:

b^2+15=8×bso

b^2+15=8b

Then we take the 8b to the other side of the equal sign so that it becomes...

b^2+15-8b=0

Hence it becomes a quadatic equation following the principle ax^2+bx+c where x is the unknown...

From there we work out to get two different numbers...either b-5=0

b=5

Or b-3=0

b=3

So the two numbers are 5 and 3

step-by-step explanation:

do you have a copy of the table?

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.