The figure below has one base
and eight lateral faces. Find its surface
area to the nearest whole number.

B

Total surface area = 320 m^2

Step-by-step explanation:

The figure is a combination of a cuboid and pyramid.

The Surface Area of a Pyramid When all side faces are the same:

[Base Area] + 1/2 × Perimeter × [Slant Length]

Let us use pythagorean theorem to calculate the slant length

Slant length = root(6^2 + 4^2)

Slant length = 7.2 m

Base area = 8 × 8 = 64 m^2

Perimeter = 8+8+8+8 = 32 m

Surface area of the pyramid will be

= 64 + ( 1/2 × 32 ) × 7.2

= 64 + 16 × 7.2

= 64 + 115.4

= 179.4 m^2

The surface area of the cuboid will be

LB + LH + BH = 8×8 + 8×5 + 8×5

= 64 + 40 + 40

= 144 m^2

Total surface area = 179.4 + 144

Total surface area = 323.4 m^2

= 320 m^2 to the nearest whole number.

you forgot an image

step-by-step explanation:

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.