Solve for Q. Reduce any fractions to lowest terms. Don’t round your answer, I don’t use mixed fractions.

50q + 43 > -11q +70

q > 27/61

Step-by-step explanation:

50q + 43 > -11q +70

Add 11 q to each side

50q+11q + 43 > -11q+11q +70

61q +43 > 70

Subtract 43 from each side

61q+43-43 > 70-43

61q > 27

Divide each side by 61

61q/61 >27/61

q > 27/61

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)