Enter all answers to the nearest tenth.

A day care program has an average daily expense of $75.00. The standard deviation is $5.00. The owner takes a sample of 64 bills. What is the probability the mean of his sample will be between $70.00 and $80.00?
Step 1. Calculate a z-score for $70.00 -
Step 2. Give the probability for step 1. %
Step 3. Calculate the z-score for $80.00 +
Step 4. Give the probability for step 3. %
Step 5. Add the probabilities from steps 2&4. %

What is  the probability the mean of his sample will be between $70.00 and $80.00? = 64/64 =1

s1) = 99% =z score = 127/128

s2)64/64 = 1

s3)95% of 64 = 123/128

s4) p) step 3 = 95% of 64 = 60.08 /64 = 60/64 = 93.75%

s5) P)of 2+4 = 283/292 = 96.92%

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: