20points. please help once again

325 adults and 612 children

A total of 937 people attended the play.  Admission was $2.00 for adults and $0.75  for students. The total ticket sales  amounted to $1,109. How many students  and adults attended the school play?  First complete the equations below, where A  stands for Adults and S stands for Students.

[325]A + [612]S = 1,109; A + S = [2.75]

325 (amount of adults)  x 2 (2 is the amount of money for each adult ticket)

= $650

937 (amount of people total in the play) - 325 (adults)

= 612 (kids)

612 x 0.75 (amount for each child)

= $459

$459 + 650 = $1109

325 + 612 = 937

so what is the problem what are they asking you to solve

step-by-step explanation:

so what is the problem what are they asking you to solve

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.