Two men decide to drive to a distant town, taking the same route. The first leaves 2 hours ahead of the second and drives at 60 km per hour, while the second man drives at 90 km per hour. How many hours will it take the second man to catch up with the first man?

4 hours.

Step-by-step explanation:

If the first guy is driving at 60 km, in 2 hours he is 120 km away. The second guy, leave two hours after. He will drive and in 2 hours he is 180 km. now if the second car keeps going then

120+ 60 + 60 +60 + 60 = 360

180 + 90 + 90 = 360.

So, the two hours for the guy going at 90 km and another 2 hours is 4 hours, so it will take 4 hours for the second driver to catch up.

the answer is simply just 6n add the two together as they have an n

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: