The perimeter of a rectangle is 42feet. The length decreased by 3times the width is 1foot . What are the dimensions of the rectangle? (what is the length and width)

Length is 16 ft. Width is 5 feet.

Step-by-step explanation: Take the information given and write an equation. "Length decreased by 3 is 1" becomes L - 3w = 1 .

"Solve" for L. L= 3w +1

Write another equation for the formula of a perimeter. P=2L + 2w.

Substitute the values for L (from the first "solution" you wrote) and P (42 ft, given).

42 = 2(3w +1) + 2w. Solve this.

42= 6w +2 + 2w

42= 8w +2. Subtract 2 from both sides then divide both sides by 8.

W = 5

Substitute that into the first equation you wrote to get the Length.

L - 3(5) = 1

L -15 = 1. L = 1+15

L = 16

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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