Find 4 consecutive odd integers whose sum is 232

 4 consecutive odd integers...
x, x + 2, x + 4, x + 6

(x) + (x + 2) + (x + 4) + (x + 6) = 232
4x + 12 = 232
4x = 232 - 12
4x = 220
x = 220/4
x = 55

x + 2 = 55 + 2 = 57
x + 4 = 55 + 4 = 59
x + 6 = 55 + 6 = 61

so ur numbers are : 55, 57, 59, 61

Idon't know the answer