Write a pair of numbers such that the value of the 7 in the first number is 1000 times the value of the 7 in the second number and the value of the 3 in the first number is 100 times the value of the three in the second number

So let's say that the first number is and the second one is .

The value of 7 in the first should be 1000 times bigger than in the second, so let's make it 7000 and 7:

z7xxx and 7

now, the value of 3 in the first number is 100 times the value of the 3 in the second number

let's make it 37xxx - then the value of 3 is 30 000 so in the second number it must be 300,
then we have 37xxx and yy3y7

let's substitute the ys and xs by 0:

37000 and 307 - that's the solution!

A: 18/15b : 7 - -8 = 15 , 12 - -6 = 18 the y variable always goes over the x variables, c : same thing a