The solutions of a quadratic equation are 5 and -1. What is the factored form of a related quadratic function?

a) f(x) = (x + 5)(x - 1)
b) f(x) = (x + 5)(x + 1)
c) f(x) = (x - 5)(x - 5)
d) f(x) = (x - 5)(x + 1)

We should find  x= 5 and x= -1

A) f(x)= (x+ 5)(x- 1)  

x= -5 and x= 1

B) f(x)= (x+ 5)(x+ 1)

x= -5 and x= -1

C) f(x)= (x- 5)(x- 5)

x= 5 and x= 5

D) f(x)= (x- 5)(x+ 1)

x= 5 and x= -1

4th option is correct xy=-10

if this was to u plzz mark me the brainliest

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15