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A student at the airport steps onto a moving sidewalk that has a velocity of 5 m/s east. He

then begins to walk at a velocity of 1 m/s east. What is the resultant velocity of the student?

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

i am not sure :

step-by-step explanation:

there still no table