The product of two consecutive integers is 72. The equation x(x + 1) = 72 represents the situation, where x represents
the smaller integer. Which equation can be factored and solved for the smaller integer?
R2 + x - 72 = 0
x2 + x + 72 = 0
* x2 + 2x - 72 = 0
x2 + 2x + 72 = 0

a

step-by-step explanation:

i think the answer is b

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)