2 Points
Francisco's credit card has an APR of 13%, calculated on the previous
monthly balance, and a minimum payment of 2%, starting the month after the
first purchase. His credit card record for the last 7 months is shown in the
table below.
End of Previous
New
Payment Finance Principal New
month balance charges received charges
balance
$0.00 $5200.00 $0.00
$0.00 $0.00 $5200.00
$5200.00
$0.00
$104.00 $56.33 $47 67 $5152.33
S5152.33 $0.00 $103.05 $55.82 $47 23 $5105.10
$5105.10 $0.00 $102.10 $55.31 $46.80 $5058,31
$5058.31 $0.00 $101.17 $54.80 $46.37 $5011.94
$5011.94 $0.00 $100.24 $54.30 $45.94 $4966.00
$4966.00 $0.00 $99.32 $53.80 $45 52 $4920.47
paid
von AWN-
How much of the $5200 charge that Francisco made during the first month
has been paid off?

the answer is b i just did that

step-by-step explanation:

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°