Suppose that in a random selection of 100100 colored candies, 2828% of them are blue. The candy company claims that the percentage of blue candies is equal to 2929%. Use a 0.010.01 significance level to test that claim. Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. Upper H 0H0: pequals=0.290.29 Upper H 1H1: pnot equals≠0.290.29 Your answer is correct. B. Upper H 0H0: pnot equals≠0.290.29 Upper H 1H1: pequals=0.290.29 C. Upper H 0H0: pequals=0.290.29 Upper H 1H1: pgreater than>0.290.29 D. Upper H 0H0: pequals=0.290.29 Upper H 1H1: pless than<0.290.29 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is nothing.

kbmflmklbhml; bmlzb; bdhzz

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .