A business owner noted the features of the 100 cars parked at the business. Here are the results:
Sunroof
11
12
1820
14
6
25
2 doors
4 doors
Given that a randomly selected car has a sunroof, find the probability the car has 4 doors.
P (4 doors | sunroof) =

The probability of a selected car being a 4 door car, given that the car has a sunroof = 0.40

Step-by-step explanation:

The complete question is presented in the attached image.

The conditional probability, of event A happening, given that event B has happened, P(A|B), is given mathematically as

P(A|B) = P(A n B) ÷ P(B)

So, the required probability of a selected car being a 4 door car, given that the car has a sunroof is given as

P (4 doors | sunroof)

= P (4 doors n sunroof) ÷ P(sunroof)

Note that the probability of an event is given as the number of elements in that event divided by the Total number of events.

P (4 doors n sunroof)

= n (4 doors n sunroof) ÷ n (total)

From the Venn Diagram in the attached image,

n (4 doors n sunroof) = 20 + 0 = 20

n (total) = 100

P (4 doors n sunroof) = (20/100) = 0.20

P(sunroof) = n(sunroof) ÷ n(total)

n(sunroof) = 12 + 18 + 20 + 0 = 50

n(total) = 100

P(sunroof) = (50/100) = 0.50

P (4 doors | sunroof)

= P (4 doors n sunroof) ÷ P(sunroof)

= (0.20/0.50) = 0.40

Hope this Helps!!!

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step-by-step explanation:

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answer:   expression= p+p*d%

price reduction + sale price = $625

sale price: $p+$p*d%

where d% is the percentage of discount

step-by-step explanation:

original price = p

price went down by $150 price reduction $p*d%

sale price= $ 475

therefore the price before sale is: $625

and the expression that shows the price before sale is: p+p*d%