Observe as seguintes situações e sua representação em linguagem matematica dois numeros x e y são tais 2x y=6 x-y=3

We have two relations

2*x*y = 6 (2 times x times y is equal to six)

x - y = 3  ( the difference between x and y is trhe)

Where whe have two variables, x and y.

To solve this system, the first step is isolation one of the variables in one of the equations, let's isolate x in the second equation.

x - y = 3

x = 3 + y

now we can replace this in the other equation and then solve it for y.

2*x*y = 6

2*(3 + y)*y = 6

6y + 2y^2 = 6

now we have the quadratic equation:

2y^2 + 6y - 6 = 0

the solutions are:

the solutions are:

y = (-6 + 9,2)/4 = 0.8

y = (-6 - 9.2)/4 = -3.8

if y = 0.8, then:

x = 3 + y = 3.8

if y = -3.8

x = 3 + y = 3 - 3.8 = -0.8

so we have two possible solutions:

(-0.8, -3.8) and (3.8, 0.8)

50-60=10

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: