Given: PA tangent to circle k(O) at A and PB tangent to circle k(O) at B. Prove: m∠P=2·m∠OAB

dude thats to long figure it

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.