A cone-shaped container has a height of 9 inches and diameter of 2.5 inches. It is filled with a
liquid that is worth $2 per cubic inch.
What is the total value of the liquid in the container?
Use 3.14 for .
Enter your answer in the box.

*pleaseee help i will mark brainliest if right*

ps, thank you

the total value of the liquid in the container is $29.4

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, a cone

The volume of a cone is expressed as

V=1/3(πr²h)

Given data

Height h= 9 inches

Radius r= diameter/2= 2.5/2= 1.25in

Substituting we have

V= 1/3(3.14)*(1.25)²*9

V= 1/3*(3.14)*14.06

V= 44.156/3

V= 14.7in³

The volume of the cone is 14.7in³

Hence If 1 in³ of liquid costs $2

14.7in³ will cost $x

x= 14.7*2

x= $29.4

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5

step-by-step explanation: