The graph of f(x) consists of 14 points. six of the points lie in quadrant i of the coordinate plane. if f(x) is an odd function, what is the greatest number of points that can lie in quadrant ii?

Answer

As, function is an odd function , it means

f(-x)= -f(x)

So, if you will draw the graph of any of the odd function, if six points lie in first quadrant, similar number of points will be in third Quadrant, as the two parts will be mirror images of each other.

The other two point will be , one is origin (0,0) and other will be a point on X axis.

You can check this ,by taking any of the polynomial function, for example ,x, x³, x+x³, etc.

So, number of points in second quadrant=0

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

i think it is c, not positive though

step-by-step explanation: