What are the solutions to the following system of equations? y = x^2 - 3x + 3

x = 3/2 + root(3)/2  or  x = 3/2 - root(3)/2

In vertex form the equation is  y = (x - 3/2)^2 + 3/4

Step-by-step explanation:

y = x^2 - 3x + 3

y = x^2  - 3x  + 9/4  - 9/4 + 3

y = (x - 3/2)^2  + 3/4

I think you want to find the roots to the equation, right?

so  

y = (x - 3/2)^2  + 3/4 = 0

(x - 3/2)^2 = -3/4

x - 3/2 =  root(-3/4)

x = 3/2 + root(3)/2  or  x = 3/2 - root(3)/2

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1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation: