Identify the equation in slope-intercept form for the line containing the point (−3,5) and parallel to y=−2/3x+53.

y=−3/2x+5/3

y=−2/3x+5

y=−2/3x+3

y=2/3x+5

Thus option C :    is correct.

Given that:

Equation of considered straight line:

Let the equation of the straight line that has to be found is given by:

It is given that the line is parallel to previous straight lines.

Which means  that slope of both the lines are same

or

Now since the second line passes through (-3,5), thus we have:

Thus the needed equation of straight line is given by:

Thus option C :    is correct.

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y=−2/3x+3

Step-by-step explanation:

I graphed the point and the equation given below. I used the same slope in the new equation as the original equation. The y-intercept is 3 because the line goes through (0,3).

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐