. A ball is thrown upward. Its height (h, in feet) is
given by the function h = 16t^2+ 64t + 34, where t is
the length of time (in seconds) that the ball has been
in the air. What is the maximum height that the ball
reaches?
A. 3 ft B. 51 ft C. 63 ft D. 67

64 feet

Step-by-step explanation:

You can solve this by completing the square and turning the equation into that of a parabola, where the uppermost vertex is the highest point in the ball's flight path.

Since the first term there is negative, the largest possible answer that you can get is if that term is 0. The only way to make it 0 is for t to be 2, so you know that that is when the highest point is. If the first term is 0, all that is left is 98, which is the highest height. However, since you initially start at 98, you only end up going 64 feet up (I guess C is the closest to that?). Hope this helps!

it is probably the graph on the bottom right.

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this