Factorise 4p + 6pq

step by step

answer fully please, thank you.

Your answer is 2p(2 + 3q).

First we can start by finding common factors in the coefficients, 4 and 6. 4 and 6 are both divisible by 2, so we can pull this out as our first factor:

2(2p + 3pq)

Now we can look for common factors regarding p and q. Both terms include p, but only one includes q, which means we can also pull the p out as another factor:

2p(2 + 3q)

The expression inside the parentheses cannot be factored anymore, so this is the final factorisation.

I hope this helps!

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