Can you have a component of a unit vector that has been simplified have 20 points

a square root of 17 in the denominator?

O

Yes it is perfectly fine

O

No. You would have to multiply JUST the denominator by square root of 17.

No. You would have to multiply JUST the numerator by square root of 17.

No. You would have to multiply BOTH the numerator and the denominator by square

root of 17.

d

step-by-step explanation:

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.

good luck on ur quiz test or homework. have a good day : )