The equation of a line is y=-1/2x-2. what is the equation of the line that is perpendicular to the first line and passes through the point (2, –2)?

Perpendicular means that the slopes are negartive inverses, aka
slope1 times slope2=-1

y=mx+b
slope=m

y=-1/2x-2
slope=-1/2

we need to find negative inverse
-1/2 times what=-1
answer is 2

y=2x+b
input the point (2,-2) to find b
(x,y)
(2,-2)
-2=2(2)+b
-2=4+b
minus 4 from both sides
-6=b
y=2x-6

the equtaion is y=2x-6