"A sample of 64 hotels in Atlanta was selected in order to determine whether or not the average room price is significantly different from $110. The average price of the rooms in the sample was $112. The population standard deviation is known to be $16. Use a 0.05 level of significance. Use this information to answer Questions 16 to 19. What should be the appropriate null and alternative hypotheses for the purpose of your analysis?"

The null and alternative hypothesis are:

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the average room price in Atlanta is significantly different from $110 (P-value=0.317) .

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average room price in Atlanta is significantly different from $110.

Then, the null and alternative hypothesis are:

The significance level is 0.05.

The sample has a size n=64.

The sample mean is M=112.

The standard deviation of the population is known and has a value of σ=16.

We can calculate the standard error as:

Then, we can calculate the z-statistic as:

This test is a two-tailed test, so the P-value for this test is calculated as:

As the P-value (0.317) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the average room price in Atlanta is significantly different from $110.

d) -1

step-by-step explanation:

step-by-step explanation:

i think you should think about the question and not look online.