A 10 foot ladder is placed 4-feet from the edge of a building. How far up the building does the ladder reach? Round your answer to the nearest tenth of a foot.
A:10.8 feet
B:9.2 feet
C:2.4 feet
D:3.7 feet

The ladder is 9.2 feet up the building

The length (L) of the ladder is given as:

The distance (d) from the edge of the building is

The distance up the ladder is the height (h) of the ladder on the wall.

This is calculated using the following Pythagoras theorem

So, we have:

Evaluate the exponents

Subtract 16 from both sides

Take square roots of both sides

Rewrite as

Hence, the ladder is 9.2 feet up the building

Read more about Pythagoras theorems at:

link

9.2 feet.  b.)

Step-by-step explanation:

This uses the Pythagorean Theorem

Do you notice that the ladder forms a right triangle with the building.

10 feet  =  hypotenuse length

4 feet  = bottom leg length

x feet = height of building

so   10^2 = 4^2  + x^2

100 = 16 + x^2

84 = x^2

x = root(84)  = 9.16515  feet   about  9.2 feet

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: