In a game, if you roll a 2 or a 3 on a 6-sided number cube, you lose a turn. NOTE: This is just using one number cube. a. What is the probability that you roll a 2 or 3, P (2 or 3)? Explain your reasoning. (2 points possible) b. What is the probability that you don’t roll a 2 or a 3, P (NOT a 2 or 3)? Explain your reasoning.

(a)1/3

(b)2/3

Step-by-step explanation:

This is a 6-sided number cube, therefore total possible outcomes, n(S)=6

(a)Probability of rolling a 2 OR 3 =P(2)+P(3)

(b)Probability of not rolling a 2 OR 3

In probability, the sum of the probability of an event and its complement is always 1.

Therefore:

P(Rolling a 2 or 3)+P(Not rolling a 2 or 3)=1

From part (a) above:

Probability of rolling a 2 OR 3=

Therefore:

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x