Find the vector equations for medians from the vertices to the three midpoints of triangle ABC with vertices A(-1,5), B(5,-2) and C(3,5).

The equation is

2y + 85x + 75 = 0

Step-by-step explanation:

Given vertices A(-1,5), B(5,-2) and C(3,5).

Suppose we want to find the median from A

First, we find the midpoint of side BC

Let the midpoint be M = ((x1 + x2)/2, (y1 + y2)/2)

= ((5+3)/2, (-2-5)/2)

= (8/2, -7/2)

= (4, -7/2)

Next, we write the equation of median with A(-1,5) and midpoint M(4,-7/2)

y = mx + c

The slope m = (y2 - y1)/(x2 - x1)

= (-7/2 - 5)/(4 + 1)

= (-17/2)/5

m = -85/2

We find the y-intercept, using A(-1,5)

x = -1, y = 5, m = -85/2

y = mx + c

5 = (-85/2)(-1) + c

c = 5- 85/2

= -75/2

y = -85x/2 - 75/2

Multiply through by 2

2y = -85x - 75

2y + 85x + 75 = 0

And this is the equation

what are you trying to solve here

step-by-step explanation:

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.