For which equation will the solutions be opposite integers?
A 3x^2– 27= 0
B. 4x^2+ 20x+25
C. x^2+ 10x + 16 = 0
D. 2x^2+ 6x +4= 0

D. 2x^2+ 6x +4= 0

Step-by-step explanation:

The quadratic equation 2x²+6x+4 = 0 solutions will have opposite integers as shown.

On factorising:

2x²+6x+4 = 0

(2x²+2x)+(4x+4) = 0

Bringing out the common factor

2x(x+1)+4(x+1) = 0

(2x+4)+(x+1) = 0

2x+4 = 0 and x+1 = 0

2x = -4 and x = -1

x = -1/2 and -1

As we can see, the solution to the quadratic equation gave us two different integers. Note that the remaining functions will give the same values as the solutions.

your answer is the frist one

hop i