75 POINTS Which equations are equivalent to y = two-thirds x minus 4 when written in slope-intercept form? Check all that apply.

3 x minus 2 y = 4

2 x minus 3 y = 12

Negative 4 (2 x minus 3 y) = negative 4 (12)

2 (x + 6) = 3 y

2 x minus 3 y = 4

Multi select 75 points

Well, Your best answer will be is

B. 2x-3y=12

C. -4(2x-3y) = -4(12).

First you have to multiply by 3

Which it give you 3y =2x -12 of the factor 2  3y = 2(x-6)  

Then after that you subtract 2x of each sides.

Because, -2x+3y = -12

Then you must multiply by -1

Because,2x -3y = 12

Than you basically multiply by -4

Which that give you -4(2x - 3y) = -4(12)

Good Luck!

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1