Choose a method that can be used to solve this system of equations by elimination.

2x – 2y = 24
4x + 7y = –40

A. Subtract 2x from both equations and solve the first equation for y.

B. Multiply the first equation by –2 and add the second equation.

C. Add the first equation to the second equation and subtract 6x from both
sides of the equation.

D. Subtract 7y from the second equation and add the first equation.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

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step-by-step explanation:

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