Any help to solve this problem. Provide steps. Thnx

284cm^2

Step-by-step explanation:

first, we split up the shape into seperate sections that we can easily find the areas of.

i will draw vertical lines in the bottom left and right, leaving me with 2 seperate rectangles and 1 irregular pentagon.

we know that these rectangles are 4x8cm, so we do 4 * 8 which gives us 32.

there are 2 of these, so 32 x 2 = 64cm^2.

now, i chose to seperarte the pentagon into a rectangle and a triangle,

and i found the height and width of the rectangle to be (18 - (4+4)) x (8+7), or 10 x 15.

the area of the rectangle is 150cm^2.

now, for the triangle.

the line through the centre of th shape is 22cm long, but we only want the part in the triangle. luckily, there are mesurements that can help us with this.

8 + 7 = 15.

22 - 15 = 7.

now we know that the height of the triangle is 7 cm.

from earlier, we also know the base, which is 10cm.

7 x 10 = 70cm^2.

now we add all these together:

70 + 150 + 64 = 284cm^2

The answer is 333 cm squared

Step-by-step explanation:

You can split the shape in the middle, to create a rectangle on the bottom and the weird looking shape on top.

You can split the weird looking shape into two trapezoids. If you find the area of one trapezoid, (a+b)h/2, you will get 189/2. The trapezoids are identical, so 189/2 +189/2 is 189.

The area of a rectangle is base times height, or 18x8, which is 144. 144+189 is 333, which is the total area.