Please Help!!

We can show that ∆ABC is congruent to ∆A′B′C′ by a translation of
(blank) unit(s) (blank) and a (blank) across the (blank) -axis.

(Graph Attached)

A translation of 1 unit to the left and a reflection across the x axis

Step-by-step explanation:

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

11

step-by-step explanation:

32.50-7.50=25

225/25=11