Given the following system of equations and their graph below, what can be determined about the slopes and y-intercepts of the system of equations? A line includes points 1 comma negative 3 and 3 comma negative 7. A line includes points 3 comma negative 7 and 6 comma negative 6. 4x + 2y = −2 x − 3y = 24 The slopes are different, and the y-intercepts are different. The slopes are different, and the y-intercepts are the same. The slopes are the same, and the y-intercepts are different. The slopes are the same, and the y-intercepts are the same.

The slopes are different, and the y-intercepts are different.

Step-by-step explanation:

When we have an equation with the form: y=mx+b

m is the slope and b is the intercept.

So, for the first equation: 4x + 2y = -2, we can solve for y as:

Then, the slope of this equation is -2 and the intercept is -1

At the same way, for the second equation: x-3y=24, we can solve for y as:

Then the slope of this equation is and the intercept is -8

Finally, we can conclude that the slopes are different, and the y-intercepts are different.

The slopes are different, and the y-intercepts are different.

Step-by-step explanation:

I'm taking the test.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}