In the diagram below secants PT & PU have been drawn from exterior point P such that the four arcs intercepted have the following ratio of measurements arc RS: arc ST:arc TI: arc UR= 1:4:4:3.

(a) If arc RE= X then write an equation that could be used to solve for x and find the value of x

(b) state the measure of each of the four arcs. RS, ST, TU, and UR

(c) find the measure of angle P

(d) draw segment UT what would be the measure of angle UTS?

Step-by-step explanation:

(a) If RS = x, then the sum of arcs around the circle is ...

  x + 4x +4x +3x = 360°

  12x = 360°

  x = 30°

__

(b) Based on the given ratios, the arc measures are computed from x. For example, ST = TU = 4x = 4(30°) = 120°

__

(c) Angle P is half the difference of arcs TU and RS:

  ∠P = (TU -RS)/2 = (120° -30°)/2

  ∠P = 45°

__

(d) Inscribed angle UTS is half the measure of the arc it intercepts. Arc RU has the measure (30° +90°) = 120°, so the measure of UTS is ...

  ∠UTS = 120°/2 = 60°

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

hi how are you doing today? if you ever need just tell me

step-by-step explanation: