A halloween assorted bag of candy contains 4 Snickers, 2 packages of M&M's, & 3 Butterfingers. What is the probability of selecting some M&M's, putting them back, and then selecting a Butterfinger? (DECIMAL FORM)

0.07

Step-by-step explanation:

First, add up all the numbers. This will be the denominator.

4+2+3=9

There are 9 pieces of candy.

Since you are randomly choosing two times you will have to multiply two fractions.

There are M&M's, and Butterfingers (You simplify)

Now you multiply these.

×=

Now make this into a decimal. To do this divide 2 and 27. which is approximately 0.07.

27/4x^6 y^8

step-by-step explanation:

4(3x^2y^4)^3 (2x^3y^5)^4

=

108x^6 y^12 /16x^12 y^20

=

108 /16x^6 y^8

=

27 /4x^6 y^8

the answer is  

a.

28 ft2

step-by-step explanation: