Mariah is playing a simple game of dice. For every 1, 4, or 6 rolled, Mariah will
win $4. For any other number, she must pay $2. How much money can Mariah
expect to win or lose?
A. Lose $3
B. Win $1
C. Win $3
D. Lose $1

Correct option: B -> win $1

Step-by-step explanation:

Mariah will win for the values of 1, 4 or 6.

These are 3 out of 6 possible values of the die, so the probability of winning is 3/6 = 50%, and the probability of losing is 100% - 50% = 50%

The expected value for winning cases is the value times the probability, so:

E(win) = 4 * 0.5 = 2

The expected value for losing cases is:

E(lose) = -2 * 0.5 = -1

So the final expected money is:

E(total) = E(win) + E(lose) = 2 - 1 = 1

So she can expect to win $1

Correct option: B

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i